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Kundan Pandey
Mar 20, 2019

If you understand kinetic energy, then you will be able to easily interpret and understand rotational kinetic energy.

Amongst the various branches of physics, classical mechanics forms one of the most interesting and intellectually demanding sections. Mechanics finds a variety of applications in construction and civil engineering projects.

Broadly classified, linear mechanics and rotational mechanics are two branches of mechanics. Kinetic energy, one of the most fundamental concepts of physics helps us understand the various finer dimensions of many concepts in higher order physics.

In linear motion, or what we more aptly refer to as one-dimensional motion, linear kinetic energy is given by the formula, K.E_{linear} = I/2mv^{2}, where, m = mass of the body and v = linear velocity.

This formula is something most of us are aware of. Analogous to the one-dimensional motion in linear mechanics, there is rotatory motion in rotational mechanics. It is basically the study of motion of bodies and objects which follow a rotatory or circular motion. Force in linear motion is equivalent to torque in rotational mechanics.

Similarly, mass in linear mechanics is analogous to moment of inertia in rotational mechanics. The beauty of physics lies in witnessing such wonderful analogies of various interrelated concepts that prove the coherence and order in the formation of this universe.

Every moving object stores in itself various forms of the energy, and the most dominant form of energy a moving object stores is kinetic energy. In cases of rotational motion, this energy comes through rotation of the object along some specific axis of rotation. Flywheels, planets, and stars rotate on their own axis which is known as spin rotation.

The formula can easily be understood by considering the rotational motion aspect of the object rotating about an axis. The total energy of a body is the sum of translational kinetic energy (E_{t}) and rotational kinetic energy (E_{r}).

The translational kinetic energy of an object is due to the translational motion of the object (in other words, motion of the center of mass) and rotational kinetic energy is due to rotation about the center of the mass.

In essence,

**K.E**_{total} = E_{t} + E_{r}

That was the formula for total kinetic energy of a body having both rotational and translational motion. E_{r}, in fact, is dependent on angular velocity (ω) and moment of inertia (I).

That was the formula for total kinetic energy of a body having both rotational and translational motion. E

Using these two, the formula for rotational kinetic energy for an object moving around a fixed rotational axis is given by,

Rotational Kinetic Energy (E_{r}) = ½ x I x ω^{2}

where I = moment of inertia

ω = angular velocity

Rotational Kinetic Energy (E

where I = moment of inertia

ω = angular velocity

The rotational kinetic energy of the Earth is around 2.14 x 10^{29}J. To calculate this, we use the formula and put in the corresponding values that are as follows:

I = moment of inertia of Earth = 8.04 x 1037 kg - m2

ω = angular velocity of earth = 7.29 x 10-5rad.s-1

I = moment of inertia of Earth = 8.04 x 1037 kg - m2

ω = angular velocity of earth = 7.29 x 10-5rad.s-1

This was a summarized information on rotational kinetic energy that is used frequently in higher order mechanics to solve numerical problems.